Question

Which contain max no of atoms 4amu of he or 4 gatom of he?

Answer 1

From the Avogadro's relationship, 6.022× 10²³atoms are equivalent to  2g/mole of He,

Using this relationship, we can calculate the number of atoms present in 4g of He.

If 2g = 6.022× 10²³atoms

∴ 4g=?

4gₓ 6.022× 10²³atoms/2g

= 1.2044ₓ 10²⁴atoms

In case of 4amu, we use the relationship

1.661×10⁻²⁴g =1amu

∴ 4amu=?

= 6.644ₓ10⁻²⁴g

From the above illustration, 4g of He has maximum number of atoms.