Question

Which describes the action of the diaphragm and chest cavity when you exhale and squeeze air from the lungs?

Answer 1

When we exhale and squeeze air out of the lungs, the diaphragm moves upward to its normal position and the chest cavity becomes smaller, allowing the carbon dioxide rich air to flow out of the body.

Therefore, option: C.

Answer 2

hey buddy!!

correct option is c.

because when we exhale we need to blow air out so we decrease the volume of our chest cavity and this is done because diaphram moves up.