Which diagram can be used to prove △ABC ~ △DEC using similarity transformations?
Triangle A B C is rotated about point C and then is dilated to form smaller triangle C E D.
Triangle A B C is reflected across side A C and then is dilated to form smaller triangle C E D.
Triangles A B C and C E D have different angle measures.
Right triangle A B C is shown. Line segment D E is drawn near point C to form triangle D E C.
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Given:
△ABC ~ △DEC
To find:
The diagram shows △ABC ~ △DEC by using similarity transformation
Step-by-step explanation:
When we rotate ΔABC at point C and then is dilated to form a smaller triangle C E D.
∴ According to fig:
∠ A = ∠ D ... (by fig)
∠C = ∠ V ... (boh are right angles)
& by angle sum property:
∠ B = ∠ E
∴ by AAA property:
= △ABC ~ △DEC
∴ Option A is the correct answer.
Please refer following fig:
Attachments:
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