which digit will not come at last place in the cube of any number.
a= 6
b=5
c=00
d=1
Answers
Answered by
1
Answer:
Answer
To determine the digits at unit's place of the cubes of given numbers, first we need to find their cubes.
1
3
=1, 2
3
=8, 3
3
=27, 4
3
=64, 5
3
=125, 6
3
=216, 7
3
=343, 8
3
=512, 9
3
=729, 10
3
=1000
The digits at unit's place are 1,8,7,4,5,6,3,2,9,0
Let's arrange them in order, we get 0,1,2,3,4,5,6,7,8,9 as digits at unit's place.
Each digit occurs at the end of some cube. Hence one cannot conclude that some number is not a cube by looking at the last digit.
Answered by
1
Answer:
Correct option is
A
60
0
∣a∣=3,∣b∣=4,∣c∣=5
a+b+c=0
⟹a+b=−c
⟹∣a+b∣=∣−c∣
⟹∣a+b∣
2
=∣−c∣
2
⟹∣a∣
2
+∣b∣
2
+2a.b=∣c∣
2
⟹9+25+2a.b=49
Also ab=3×5
Hence 9+25+2abcosθ=49
⟹15=30cosθ
Or cosθ=
2
1
θ=60
0
so angle is 60
0
.
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