Question

which does not exist ?
i) [CCl6]²-
ii) [SiCl6]²-
iii)[GeFe]²-
iv)[SnCl6]²-
​

Answer 1

Answer:

[CCl₆]²⁻ is the compound that does not exist.

Explanation:

[CCl₆]²⁻ is the compound that does not exist.

This compound does not exist because carbon is a 2nd-period element.

So it has only 2 orbitals s and p with a valency of 4.

And there is no way that carbon can extend its valency as it has no d-orbital.

Because of this [CCl₆]²⁻ cannot exists.

While Si, Ge, Sn has d orbital though they belong to the same group as carbon they can extend their valency higher than 4.

Answer 2

Answer:

$[ CCl6]^{2-}$ doesn't exists.

Explanation:

• Carbon has valency 4.

• In the compound [CCl6]²- , the number of Chlorine atoms attached to carbon atom is $6.$

• The number of the chlorine atom, i.e 6 is more than the valency of carbon which is 4.
• Also, Carbon cannot expand its coordination number beyond four. It is due to the absence of d-orbitals.

Hence, it cannot form [ CCl6]2- ion.

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