Chemistry, asked by beenathanupillai, 8 months ago

which element with last subshell to be 4s2 4p4

Answers

Answered by dnrao34665

0

Answer:

Se(Selenium) - 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^4

= 34

Se=34(atomic number)

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