Which equation does not have m = 42 as a solution?
m/7=6
m/42=1
m/4=13
m/21=2
Answers
Answer:
m/4 = 13 is incorrect
Step-by-step explanation:
as when 42 is divided by 4 it leaves quotient as 10.5
Step-by-step explanation:
(i) x + 3 = 0
LHS = x + 3
Put x = 3, we get
LHS = 3 + 3 = 6 ≠ RHS
So, the equation is not satisfied.
(ii) x + 3 = 0
LHS = x + 3
Put x = 0, we get
LHS = 0 + 3 = 3 ≠ RHS
So, the equation is not satisfied.
(iii) x + 3 = 0
LHS = x + 3
Put x = -3, we get
LHS = -3 + 3 = 0 = RHS
So, the equation is satisfied.
(iv) x - 7 = 1
LHS = x - 7
Put x = 7, we get
LHS = 7 - 7 = 0 ≠ RHS
So, the equation is not satisfied.
(v) x - 7 = 1
LHS = x - 7
Put x = 8, we get
LHS = 8 - 7 = 1 = RHS
So, the equation is satisfied.
(vi) 5x = 25
LHS = 5x
Put x = 0, we get
LHS = 5 * 0 = 0 ≠ RHS
So, the equation is not satisfied.
(vii) 5x = 25
LHS = 5x
Put x = 5, we get
LHS = 5 * 5 = 25 = RHS
So, the equation is satisfied.
(viii) 5x = 25
LHS = 5x
Put x = -5, we get
LHS = 5 * (-5) = -25 ≠ RHS
So, the equation is not satisfied.
(ix) m/3 = 2
LHS = m/3
Put m = -6, we get
LHS = -6/3 = -2 ≠ RHS
So, the equation is not satisfied.
(x) m/3 = 2
LHS = m/3
Put m = 0, we get
LHS = 0/3 = 0 ≠ RHS
So, the equation is not satisfied.
(xi) m/3 = 2
LHS = m/3
Put m = 6, we get
LHS = 6/3 = 2 = RHS
So, the equation is satisfied.
Question 2:
Check whether the value given in the brackets is a solution to the given equation or not:
(a) n + 5 = 19 (n = 1) (b) 7n + 5 = 19 (n = -2) (c) 7n + 5 = 10 (n = 2)
(d) 4p – 3 = 13 (p = 1) (e) 4p – 3 = 13 (p = -4) (f) 4p – 3 = 13 (p = 0)
Answer:
(a) n + 5 = 19 (n = 1)
LHS = n + 5
Put n = 1 in LHS, we get
LHS = 1 + 5 = 6 ≠ RHS
So, n = 1 is not the solution of given equation.
(b)7n + 5 = 19 (n = -2)
LHS = 7n + 5
Put n = -2 in LHS, we get
LHS = 7 * (-2) + 5 = -14 + 5 = -9 ≠ RHS
So, n = -2 is not the solution of given equation.
(a) 7n + 5 = 19 (n = 2)
LHS = 7n + 5
Put n = 2 in LHS, we get
LHS = 7 * 2 + 5 = 14 + 5 = 19 = RHS
So, n = 2 is the solution of given equation.
(d) 4p – 3 = 13 (p = 1)
LHS = 4p - 13
Put p = 1 in LHS, we get
LHS = 4 * 1 - 3 = 4 - 3 = 1 ≠ RHS
So, p = 1 is not the solution of given equation.
(e) 4p – 3 = 13 (p = -4)
LHS = 4p - 13
Put p = -4 in LHS, we get
LHS = 4 * (-4) - 3 = -16 - 3 = -19 ≠ RHS
So, p = -4 is not the solution of given equation.
(f) 4p – 3 = 13 (p = 0)
LHS = 4p - 13
Put p = 0 in LHS, we get
LHS = 4 * 0 - 3 = 0 - 3 = -3 ≠ RHS
So, p = 0 is not the solution of given equation.