Which equation has a constant of proportionality equal to \dfrac{1}{2} 2 1 start fraction, 1, divided by, 2, end fraction? Choose 1 answer: Choose 1 answer: (Choice A) A y=2xy=2xy, equals, 2, x (Choice B) B y=4xy=4xy, equals, 4, x (Choice C) C y=\dfrac{3}{6}xy= 6 3 XY, equals, start fraction, 3, divided by, 6, end fraction, x (Choice D) D y=\dfrac{3}{4}xy= 4 3 x
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Given : y = 2x , y = 4x , y = (3/6)x , y = (3/4)x
To Find : Which equation has a constant of proportionality equal to 1/2)
Solution:
proportional relationships
y ∝ x
=> y = kx
k is a constant of proportionality
y = 2x
k = 2
y = 4x
k = 4
y = (3/6)x
=> y = (1/2) x
k = 1/2
y = (3/4)x
=> k = 3/4
y = (3/6)x has a constant of proportionality equal to 1/2
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