Question

Which equation is the root of x = -1?​

Answer 1

Answer:

Step-by-step explanation:

A nonnegative number that must be multiplied times itself to equal a given number. The square root of x is written or x½.

Answer 2

Answer:

Solve for x:

1/(x - 1) = x/6 + x/(x - 1)

Bring x/6 + x/(x - 1) together using the common denominator 6 (x - 1):

1/(x - 1) = (x (x + 5))/(6 (x - 1))

Cross multiply:

6 (x - 1) = x (x - 1) (x + 5)

Expand out terms of the left hand side:

6 x - 6 = x (x - 1) (x + 5)

Expand out terms of the right hand side:

6 x - 6 = x^3 + 4 x^2 - 5 x

Subtract x^3 + 4 x^2 - 5 x from both sides:

-x^3 - 4 x^2 + 11 x - 6 = 0

The left hand side factors into a product with three terms:

-(x - 1)^2 (x + 6) = 0

Multiply both sides by -1:

(x - 1)^2 (x + 6) = 0

Split into two equations:

(x - 1)^2 = 0 or x + 6 = 0

Take the square root of both sides:

x - 1 = 0 or x + 6 = 0

Add 1 to both sides:

x = 1 or x + 6 = 0

Subtract 6 from both sides:

x = 1 or x = -6

1/(x - 1) ⇒ 1/(-1 - 6) = -1/7

x/6 + x/(x - 1) ⇒ -6/(-1 - 6) + -6/6 = -1/7:

So this solution is correct

1/(x - 1) ⇒ 1/(1 - 1) = ∞^~

x/6 + x/(x - 1) ⇒ 1/(1 - 1) + 1/6 = ∞^~:

So this solution is incorrect

The solution is:

Answer: x = -6 there is only one Root