Question

Which equation is y = –3x2 – 12x – 2 rewritten in vertex form?

Answer 1

Answer:

The vertex form of the given parabola is $y=-3(x+2)^2+10$.

Step-by-step explanation:

The vertex form of the parabola is

$y=a(x-h)^2+k$

Where, (h,k) is vertex and a is a constant.

The given equation is

$y=-3x^2-12x-2$

$y=-3(x^2+4x)-2$

$(\frac{-b}{2a})^2=(\frac{-4}{2(1)})^2=4$

Add and subtract 4 in the parenthesis.

$y=-3(x^2+4x+4-4)-2$

$y=-3(x^2+4x+4)-3(-4)-2$

$y=-3(x+2)^2+10$

The vertex of the parabola is (-2,10).

Therefore the vertex form of the given parabola is $y=-3(x+2)^2+10$.

Answer 2

Answer:

The answer is A- y = –3(x + 2)2 + 10

Step-by-step explanation:

got it right on edge