Question

Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)?
Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot
(x – 4)2 + y2 = 100
(x – 4)2 + y2 = 10
x2 + (y – 4)² = 10
x2 + (y – 4)² = 100

Answer 1

Step-by-step explanation:

(x - 4)² + (y)² = 100

Data Circle Center = (4, 0)

Point = ( -2, 8)

Equations Distance = √(x2 - x1)² + (y2 - y1)²

Circle (x - h)² + (y - k)² = r²

Process Find r = √(x2 - x1)² + (y2 - y1)² r = √(-2 - 4)² + (8 - 0)²

r = √ (-6)² + (8)²

r = √ 36 + 64

r = √ 100

r = 10Circle

(x - 4)² + (y - 0)² = (10)²

(x - 4)² + (y)² = 100