Question

Which equation represents a graph with a vertex at (–3, 2)? y = 4x2 + 24x + 38 y = 4x2 – 24x + 38 y = 4x2 + 12x + 2 y = 4x2 + 16x + 13

Answer 1

Answer:

$y = 4x^2 + 24x + 38$ equation represents a graph with a vertex at (–3, 2).

Step-by-step explanation:

$y=4(x+3)^2+2$

The vertex form of a parabola is given by $y=a(x-h)^2+hk$

where (h,k) is the vertex

$y=4x^2+24x+36+2=4x^2+24x+38$

From the given options the correct equation whcih exactly compares with our solution is :

$y = 4x^2 + 24x + 38$ equation represents a graph with a vertex at (–3, 2).

Answer 2

Answer:

y = 4x² + 24x + 38

y = 4x² + 12x + 2

Step-by-step explanation:

Which equation represents a graph with a vertex at (–3, 2)? y = 4x2 + 24x + 38 y = 4x2 – 24x + 38 y = 4x2 + 12x + 2 y = 4x2 + 16x + 13

vertex at (–3, 2) = x = -3 & y =2

y = 4x² + 24x + 38

=>y =4(-3)² + 24(-3) + 38

=>y = 36 -72 + 38

=> y = 2 = 2

y = 4x² + 24x + 38

y = 4x² - 24x + 38

=>y =4(-3)² - 24(-3) + 38

=>y = 36 +72 + 38

=> y = 136 ≠ 2

y = 4x² + 12x + 2

=>y =4(-3)² + 12(-3) + 2

=>y = 36 -36 + 2

=> y = 2 = 2

y = 4x² + 12x + 2

y = 4x² + 16x + 13

=>y =4(-3)² + 16(-3) + 13

=>y = 36 -48 + 13

=> y = 4 ≠ 2