Which expression is equivalent to 7\dfrac34 - \dfrac127
4
3
−
2
1
7, start fraction, 3, divided by, 4, end fraction, minus, start fraction, 1, divided by, 2, end fraction?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
\dfrac12+\left(-7\dfrac34\right)
2
1
+(−7
4
3
)start fraction, 1, divided by, 2, end fraction, plus, left parenthesis, minus, 7, start fraction, 3, divided by, 4, end fraction, right parenthesis
(Choice B)
B
\dfrac12+7\dfrac34
2
1
+7
4
3
start fraction, 1, divided by, 2, end fraction, plus, 7, start fraction, 3, divided by, 4, end fraction
(Choice C)
C
-7\dfrac34+\left(-\dfrac12\right)−7
4
3
+(−
2
1
)minus, 7, start fraction, 3, divided by, 4, end fraction, plus, left parenthesis, minus, start fraction, 1, divided by, 2, end fraction, right parenthesis
(Choice D)
D
7\dfrac34+\left(-\dfrac12\right)7
4
3
+(−
2
1
)
Answers
Answer:
7]=+(-7)
Step-by-step explanation:
l hope you understand
Answer:
B) \dfrac12+7\dfrac34+ \dfrac{7}{4} = \dfrac{1}{2}+\dfrac{28}{4}+ \dfrac{7}{4} = \dfrac{35}{4}
Step-by-step explanation:
We start with the expression:
7\dfrac34 - \dfrac127
We can rewrite the mixed number 7\dfrac34 as an improper fraction:
7\dfrac34 = \dfrac{7 \times 4}{4} + \dfrac{3}{4} = \dfrac{28}{4} + \dfrac{3}{4} = \dfrac{31}{4}
Now we have:
\dfrac{31}{4} - \dfrac{1}{2}
To subtract fractions, we need to find a common denominator. The least common multiple of 2 and 4 is 4, so we can convert both fractions to have a denominator of 4:
\dfrac{31}{4} - \dfrac{1}{2} = \dfrac{31 \times 2}{4 \times 2} - \dfrac{1 \times 2}{2 \times 2} = \dfrac{62}{8} - \dfrac{2}{4} = \dfrac{62}{8} - \dfrac{1}{2}
Now that the two fractions have a common denominator of 8, we can subtract them:
\dfrac{62}{8} - \dfrac{1}{2} = \dfrac{62}{8} - \dfrac{4}{8} = \dfrac{58}{8} = \dfrac{29}{4}
So the final answer is:
\dfrac{29}{4}
Another way to express this is as a mixed number:
\dfrac{29}{4} = 7\dfrac{1}{4}
Therefore, the expression 7\dfrac34 - \dfrac127 is equivalent to 7\dfrac{1}{4}, which is the same as answer choice B: \dfrac12+7\dfrac34+ \dfrac{7}{4} = \dfrac{1}{2}+\dfrac{28}{4}+ \dfrac{7}{4} = \dfrac{35}{4}
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