Question

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m n Superscript negative 2 Baseline EndFraction? Assume m not-equals 0, n not-equals 0.

Answer 1

Step-by-step explanation:

Given Which expression is equivalent to Start Fraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m n Superscript negative 2 Baseline End Fraction?

Assume m not-equals 0, n not-equals 0.

• So the given expression is (3m^-2n)^-3 / 6mn^-2
• So using law of exponents we have (a^m)^n = a^mn
• So we can write the above expression as  
•        3^-3 m^6 n^-3 / 6 m n^-2 ( where m ≠ 0 and n ≠ 0)
•       So m^6 n^- 3 / 3^3 x 6 mn^-2
•      So m^6 n^-3 / 3^3 x 6 mn^-2
• Using law of exponents (a^m x a^n = a^m+n)
•      So we get  
•  m^5 n^-1 / 162
•  Or m^5 / 162 n

Reference link will be

https://brainly.in/question/17992928

Answer 2

Answer:

b

Step-by-step explanation:

i took the test and its right 81m^2n^5/8