Question

Which figure encloses more area: a square of Side 2 cm; a rectangle of side 3 cm and 2 cm or an equilateral triangle of side 4 cm?
How?​

Answer 1

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area of square =s^2

=2^2

=4cm^2

area of rectangle=lb

=3x2

=6cm^2

area of equilateral triangle=bh/2

b=4,h=x

h=√(4^2+2^2)

=√(16+4)

=√20

=2√5cm

area=(4x2√5)/2

=(8√5)/2

=4√5cm^2

hence area of rectangle is more

Answer 2

Step-by-step explanation:

Area enclosed by the square = 2^2 = 4cm^2

Area enclosed by the rectangle = 2*3 = 6cm^2

Area enclosed by the equilateral triangle = √3/4 a^2 where a is the length of the side

=> area = √3/4 x 4 x 4

= 4√3

= approximately 6.93 cm^2

Since 6.93 > 6 > 4 ,

Hence, the equilateral triangle encloses the most area