which form of the AP i 3, 15, 27,39..
will be 132 more than its 54th. term
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Answer:
a=3
a2=15
d=a2-a= 15-1=14
an =a+(n-1) d
an= 3+(54-1) 12
an=3+636
an=639
132 more means adding an with 132
an+132
639+132=771
now new an =771
an=a+(n-1) d
771=3+(n-1) 12
771=3+12n-12
771=-9+12n
771+9=12n
780=12n
n=780/12
n= 65
hope it is helpful...
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