Math, asked by cemerine6950, 1 year ago

Which function has an inverse that is also a function? {(–1, –2), (0, 4), (1, 3), (5, 14), (7, 4)} {(–1, 2), (0, 4), (1, 5), (5, 4), (7, 2)} {(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)} {(–1, 4), (0, 4), (1, 2), (5, 3), (7, 1)}

Answers

Answered by HappiestWriter012
9

Function : {(–1, –2), (0, 4), (1, 3), (5, 14), (7, 4)}

Inverse relation : {(–2, –1), (4, 0), (3, 1), (14, 5), (4, 7)}

For the element 4 in the domain , There are two images 0, 7

So the Inverse is not a function.

Function : {(–1, 2), (0, 4), (1, 5), (5, 4), (7, 2)}

Inverse relation : {(2 , - 1 ), (4, 0), (5, 1), (4, 5), (2, 7)}

For the element 2 in the domain, There are two images 7, - 1

So the Inverse is not a function.

Function : {(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)}

Inverse relation : {(3, - 1), (4, 0), (14, 1), (6, 5), (2, 7)}

All the elements in the domain have a single image.

So the Inverse is a function.

Function : {(–1, 4), (0, 4), (1, 2), (5, 3), (7, 1)}

Inverse relation : (4, - 1), (4, 0), (2, 1), (3, 5), (1, 7)}

For the element 4 in the domain , There are two images - 1, 0

So the Inverse is not a function.

Answered by hawthornemaci
7

Answer:

C

Step-by-step explanation:

took quiz :)

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