Question

Which function has real zeros at x = –8 and x = 5? g(x) = x2 3x – 40 g(x) = x2 3x 40 g(x) = x2 14x – 40 g(x) = x2 14x 40

Answer 1

Answer:

$g(x)=x^2+3x-40$

Step-by-step explanation:

We are given two real zeros x=-8 and x=5

If two roots are a and b then function is (x-a)(x-b)

Function of given zeros is

g(x)=(x-(-8))(x-5)

g(x)=(x+8)(x-5)

$g(x)=x^2+8x-5x-40$

$g(x)=x^2+3x-40$

Thus, Option A is correct.