Question

Which functions have an axis of symmetry of x = –2? Check all that apply. f(x) = x2 + 4x + 3 f(x) = x2 – 4x – 5 f(x) = x2 + 6x + 2 f(x) = –2x2 – 8x + 1 f(x) = –2x2 + 8x – 2

Answer 1

Answer:

All you need to check is which parabola has its vertex at x = - 2

( Since parabola is symmetric to its axis , which passes through vertex )

$for\: \: a {x}^{2} + bx + c = 0 \\ \\ vertex = \frac{ - b \: \: }{ \: 2a}$

Check option 1st us right

Answer 2

Answer:

for a*²+b*+c =0

vertex=-b\2a

1st right