Question

which gives the following criterion 10)
8.4.3 SAS CRITERION FOR SIMILARITY OF TRIANGLES
Theorem-8.5: If one angle of a triangle is equal to one angle of the other triangle and the sides
including these angles are proportional, then the two triangles are similar.
D
Given : In AABC and ADEF
AB
AC
(<1) and
DF
DE
P,
AQ
ZA = ZD
RTP: AABC ~ ADEF
B
C
E
Construction : Locate points P and Q on DE and DF respectively such that AB = DP and
AC = DQ. Join PQ.
Proof : PQ || EF and AABC = ADPQ (How ?)
So ZA = ZD, ZB = ZP, ZC = ZQ
AABC~ ADEF (why?)​

Answer 1

Answer:

the answer is therefore not working plz tell