Question

Which graph is the sequence defined by the function f(x)=3(2)^x-1

Answer 1

Step-by-step explanation:

Heya mate

Here's ur answer

Given:

f(x) = 3(2)x-1

so, y = 6x -1

Now, to graph the equation, we need to have x and y intercepts.

To find x-intercept, substitute y=0 in the equation.

0 = 6x - 1

=> 6x = 1

=> x =1/6 = 0.17

To find y-intercept, substitute x = 0 in the equation.

y = 6(0) -1

=> y =-1

The given equation is linear and passes through the points (0,-1) and (0.17,0).

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Answer 2

Answer:

Given..f(X)=3(2)^x-1 so y= 6x-1

Now,to graph the equation we need X and y intercepts.

To find X intercepts, substitute y=o in the equation.

0=6x-1

6x=1

X=1/6=0.17

To find y intercepts, substitute X=0 in the equation.

y=6(0)-1

y=-1

The equation is linear and passes through the point (0,-1) and (0.17,0)

Step-by-step explanation:

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