Question

Which graph represents the function f(x) = –x2 + 5?

Answer 1

Answer:

The graph in the attached figure

Step-by-step explanation:

we have the quadratic function

f(x)=-x^{2}+5f(x)=−x

2 +5

This is a vertical parabola open downward

The vertex is a maximum

Remember that

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^2+ky=a(x−h)

2+k

where

a is a coefficient

(h,k) is the vertex

In this problem

a=-1

(h,k)=(0,5) ----> vertex

The y-intercept is the point (0,5) ---> value of y when the value of x is equal to zero (is the same point that the vertex)

The x-intercepts are the points (\sqrt{5},0),(-\sqrt{5},0)(

5

,0),(− 5 ,0) --->values of x when the value of y is equal to zero

using a graphing tool

The graph in the attached figure

hope it help u

mark me Branilest