Question

Which greatest 5-digit number when divided by 64 leaves 12 as remainder
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Answer 1

Answer:

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Step-by-step explanation:

What is the greatest 5 digit number

48=24×3

L.C.M. (8, 14, 18, 24, 48)=24×32×7=1008

1008+6=1014

∴1014 is the smallest 4 digit number which leaves a remainder of 6

When divided by 8, 14, 18, 24 and 48

The largest 5 digit number is 99999.

99999÷1014≈98.61

1014+1008×98=99798is the largest integer which leaves a remainder

of 6 when divided by 8, 14, 18, 24 and 48

99798=12474×8+6

99798=7128×14+6

99798=5544×18+6

99798=4158×24+6

99798=2079×48+6