Math, asked by bijaysahu82244, 5 months ago

which greatest 5 digit number when divided by 64 leaves 12 as remainder ​

Answers

Answered by dps27524gst
1

Answer:

make it brillint

Step-by-step explanation:

The LCM of

8 = 2x2x2

14 = 2x7

18 = 2x3x3

24 = 2x2x2x3

48 = 2x2x2x2x3

LCM = 2x2x2x2x3x3x7 = 1008

Divide 100000 by 1008 to get 99.2.

Multiply 99 by 1008 and add 7 to get 99792+7 = 99799 as the largest 5-digit number divisible by 8, 14, 18, 24 and 48 leaving a remainder of 7 in each case.

Check: 99799/8 = 12474 as quotient and a remainder of 7. Correct.

99799/14 = 7128 as quotient and a remainder of 7. Correct.

99799/18 = 5544 as quotient and a remainder of 7. Correct.

99799/24 = 4158 as quotient and a remainder of 7. Correct.

99799/48 = 2079 as quotient and a remainder of 7. Correct.

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