Question

which has highest osmotic pressure 0.1 m urea, K2SO4, Nacl, 0.01m urea ​

Answer 1

Answer:

Explanation:

Sodium choride

Answer 2

The osmotic pressure is the highest for 0.1 M $K_2SO_4$

Explanation:

To calculate the osmotic pressure, we use the equation:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution

i = Van't hoff factor

M = molarity of solute

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution

For the given options:

• Option 1:  0.10 M $K_2SO_4$

Value of i = 3

So, molar concentration will be = $(0.1)\times 3=0.3M$

• Option 2:  0.1 M NaCl

Value of i = 2

So, molar concentration will be = $(0.1)\times 2=0.2M$

• Option 3:  0.01 M urea

Value of i = 1  (for non-electrolytes)

So, molar concentration will be = $(0.01)\times 1=0.01M$

As, the molar concentration of $K_2SO_4$  is the highest, so its osmotic pressure will be the highest.

Learn more about osmotic pressure:

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