Which has lowest wavelength explain ur answer... 1.lymen series. 2. Balmer series. 3. Bracket series 4. Humphrey series
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For Lyman series n1=1n1=1
For shortest λλ of Lyman series; energy difference in two levels showing transition should be maximum i.e n2=∞n2=∞
1λ=RH[112−1∞2]1λ=RH[112−1∞2]
1λ=1096781λ=109678
λ=911.7×10−8cmλ=911.7×10−8cm
=911.7A∘
transition should be minimum i.e n2=2n2=2
1λ=RH[112−122]1λ=RH[112−122]
=109678×34=109678×34
λ=1215.67×10−8cmλ=1215.67×10−8cm
=1215.67A∘
Lyman series
For shortest λλ of Lyman series; energy difference in two levels showing transition should be maximum i.e n2=∞n2=∞
1λ=RH[112−1∞2]1λ=RH[112−1∞2]
1λ=1096781λ=109678
λ=911.7×10−8cmλ=911.7×10−8cm
=911.7A∘
transition should be minimum i.e n2=2n2=2
1λ=RH[112−122]1λ=RH[112−122]
=109678×34=109678×34
λ=1215.67×10−8cmλ=1215.67×10−8cm
=1215.67A∘
Lyman series
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Answer:
1. Lyman Series
Explanation:
For Lyman series n1=1n1=1
For shortest λλ of Lyman series; energy difference in two levels showing transition should be maximum i.e n2=∞n2=∞
1λ=RH[112−1∞2]1λ
=RH[112−1∞2] 1λ
=1096781λ=109678
λ=911.7×10−8cm
λ=911.7×10−8cm
=911.7A∘
transition should be minimum i.e n2=2n2=2
1λ= RH[112−122]1λ
= RH[112−122]
= 109678×34
= 109678×34
λ=1215.67×10−8cm
Hence, Lyman Series.
hope it helps! :)
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