Question

Which has maximum no. Of molecules a)1 g of CO2 b)1 g of N2 c)1g of H2 d)1g of ch4

Answer 1

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$\frac{ { {..1 = 0 \times \frac{?}{?} }^{?} }^{2} }{?} \times \frac{?}{?}$

Answer 2

1g of CO2=1/44×NA×3=3NA/44=0.06NA
1g of N2=1/28×NA×2=NA/14=0.07NA
1g of H2=1/2×NA×2=NA
1g of CH4=1/16×NA×5=5NA/16=0.31NA
where NA is avagadro number =6.023×10^23
1g of CH4 has maximum no. of molecules