Question

Which has maximum number of atoms?
(a) 24g of C (12) (b) 56g of Fe (56) (c) 27g of Al (27) (d) 108g of Ag (108)

Answer 1

a> no. of moles = 24/12

= 2

so, no. of atoms = no. of moles * Na

= 2Na

b> no. of moles = 56/56

= 1

so, no. of atoms = no. of moles * Na

= 1*Na

= Na

c> no. of moles = 27/27

= 1

so, no. of atoms = no. of moles * Na

= 1*Na

= Na

d> no. of moles = 108/108 = 1

so, no of atoms = no.of moles * Na

= 1*Na

= Na

Now, as 2Na is largest so, 24g of C-12 has maximum number of atoms.