Question

Which has more atoms 100g of sodium or 100g of Iron.[Na=23,Fe=56]​

Answer 1

Answer:

sodium

Explanation:

given mass of Na=100g, molar mass of Na=23

no. of moles of Na=given mass/molecular mass

=100/23=4.37

no. of atoms of Na= 4.37×6.022×10^23

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similarly no. of moles of Fe=100/56=1.78

no. of atoms of Fe = 1.78×6.022×10^23

therefore sodium has more atoms

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Answer 2

Given

Atomic mass of Na = 23 u

Atomic mass of Fe = 56 u

Then, gram atomic mass of Na = 23 g

Now, 23 g of Na contains = 6.022 x 1023 g number of atoms

Thus, 100 g of Na contains = 6.022 x 1023 / (23 x 100 number of atoms)

 100 g of Na contains = 2.6182 x 1024 number of atoms

Then, gram atomic mass of Fe = 56 g

Now, 56 g of Fe contains = 6.022 x 1023 g number of atoms

Thus, 100 g of Fe contains = 6.022 x 1023 / (56 x 100 number of atoms)

100 g of Fe contains = 1.0753 x 1024 number of atoms

Therefore, 100 grams of sodium contains more number of atoms than 100 grams of iron.