Which has more number of atoms -
100g of
Sodium or 100 g of
iron
no irrelevant answers are required
Answers
Explanation:
We know that:
Atomic mass of Na = 23 u
Atomic mass of Fe = 56 u
Then, gram atomic mass of Na = 23 g
Now, 23 g of Na contains = 6.022 x 1023 g number of atoms
Thus, 100 g of Na contains = 6.022 x 1023 / (23 x 100 number of atoms)
100 g of Na contains = 2.6182 x 1024 number of atoms
Then, gram atomic mass of Fe = 56 g
Now, 56 g of Fe contains = 6.022 x 1023 g number of atoms
Thus, 100 g of Fe contains = 6.022 x 1023 / (56 x 100 number of atoms)
100 g of Fe contains = 1.0753 x 1024 number of atoms
Therefore, 100 grams of sodium contains more number of atoms than 100 grams of iron.
Answer:
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Here is your answer......
Explanation:
Given,
mass of Na = 100 g ;molar mass of Na= 23g.
No. of moles of Na = 100 = 4.343
23
No. of atoms of Na = 4.35× NA.
(NA is the Avogadro no.)
Given,
mass of Fe = 100 g ; molar mass of Fe = 56g
No. of moles of Fe =100 =2.10
56
No. of atom of Fe= 2.10× NA
(Na is the Avogadro No)
So, Na has more no. of atoms .