Question

Which has more number of atoms, 100g of sodium or 100g of iron?

Answer 1

$<b>$Here is the answer to your question!!

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No. of moles of Na = 100/23 = 4.34 moles.

No. of. moles of Friends = 100/56 = 25/14 = 1.79 moles.

Since, number of moles of Na are more than number of moles of Feeling, therefore, 10p g of Mass contain more number of atoms.

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Answer 2

To be found :-

which has more number of atoms, 100 g of sodium or 100 g of iron

So,

As we know that,

Sodium (Na) = 23 u  (atomic mass)

and

Iron (Fe) = 56 u (atomic mass)

Solution :

23 g atomic unit or 23 g (1 mole) Na = 6.022 × 10²³ atoms

So, therefore

100 g of sodium contains = $\bf \frac{6.022\times{10}^{23}}{23}\times 100\:\:atoms$

                                          = 2.617 × 10²⁴ atoms

now,

56 g atomic  unit or 56 g (1 mole) iron = 6.022 × 10²³ atoms

So, therefore

100 g iron contains = $\bf \frac{6.022\times{10}^{23}}{56}\times 100\:\:atoms$

                                 = 1.075 × 10²⁴ atoms

Hence,

100 g of Na (Sodium) has more atoms than 100 g of Fe (Iron)