Which has more number of atoms 20 g of boron or 20 g of oxygen given mass B=11 U o 16 U?
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Case 1 : oxygen (O)
W = 20 g
M = 16 g/mol.
Thus n = W/M
- n = 20 / 16
- n = 5/4
- n = 1.25 moles
Thus N = n × NA
- N = 1.25 × 6.022 × 10²³
- N = 7.52 × 10²³ atoms.
Case 2 : Boron (B)
W = 20 g
M = 11 g/mol.
Thus n = W/M
- n = 20/11
- n = 1.81 moles
Thus N = n × NA
- N = 1.81 × 6.022 × 10²³
- N = 10.89 × 10²³ atoms
Thus Boron has more number of atoms.
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