Question

Which has the highest number of molecules at STP ?
A) 3liter of OXYGEN
B) 5liter if CHOLINE
C) 6liter of HYDROGEN
D) 1liter of ARONG

Answer 1

Answer:

c 6liter of hydrogen

Explanation:

because water consists mainly of hydrogen

Answer 2

Answer:

6L of Hydrogen has high molecules.

Explanation:

A) 3L of Oxygen

At STP, One mole of any ideal gas occupies a volume of 22.4 L.

So, moles oxygen $=\frac{3 L}{22.4 L}=0.13 \mathrm{moles} \text { of } O_{2}$

1 mole $=6.022 \times 10^{23} \text { molecules }$

Thus molecules of $O_{2}=\text { moles } O_{2} \times 6.022 \times 10^{23} \text { molecules }$

$=0.13 \times 6.022 \times 10^{23} \text { molecules }$

$=0.78 \text { molecules }$

B) 5L of chlorine

At STP, One mole of any ideal gas occupies a volume of 22.4 L.

So, moles chlorine $=\frac{5 L}{22.4 L}=0.22 \text { moles of } C l$

$1 \text { mole }=6.022 \times 10^{23} \text { molecules }$

Thus molecules of $\mathrm{Cl}=\text { moles } \mathrm{Cl} \times 6.022 \times 10^{23} \text { molecules }$

$=0.22 \times 6.022 \times 10^{23} \text { molecules }$

$=1.32 \text { molecules }$

C) 6L of Hydrogen

At STP, One mole of any ideal gas occupies a volume of 22.4 L.

So, moles hyrogen $=\frac{6 L}{22.4 L}=0.26 \text { moles of } H_{2}$

$1 \text { mole }=6.022 \times 10^{23} \text { molecules }$

Thus molecules of$H_{2}=\text { moles } H_{2} \times 6.022 \times 10^{23} \text { molecules }$

$=0.26 \times 6.022 \times 10^{23} \text { molecules }$

=1.56 molecules  

D) 1L of Argon

At STP, ‘One mole of any ideal gas’ occupies a volume of 22.4 L.

So, moles Argon $=\frac{1 L}{22.4 L}=0.04 \mathrm{moles} \text { of } \mathrm{Ar}$

$1 \text { mole }=6.022 \times 10^{23} \text { molecules }$

Thus molecules of $A r=m o l e s A r \times 6.022 \times 10^{23} \text { molecules }$

$=0.04 \times 6.022 \times 10^{23} \text { molecules }$

=0.24 molecules