Question

Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

Answer 1

answer of your question is n-99.4

Answer 2

Answer: The recursive formula for the sequence is given by

$f(n+1)=f(1)-99.4n$

Step-by-step explanation:

Since we have given that

$f(1)=99.4$ and

99.4,0,-99.4,-198.8

Here, first term = 99.4

common difference is given by

$a_2-a_1=0-99.4=-99.4$

So, it becomes

$f(n+1)=f(1)+(n)(-99.4)\\\\f(n+1)=f(1)-99.4n$

Hence, the recursive formula for the sequence is given by

$f(n+1)=f(1)-99.4n$