Question

which is bigger in area : a rectangle 13 m in length and 9 m in breadth or a square of 12 m side ? With full explanation​

Answer 1

Area of rectangle=(l×b)

=(13×9)m^2

=117m^2

Area of square=(side)^2

=(12)m^2

=144m^2

Hence,Area of square is bigger than the area of rectangle .

Answer 2

AnswEr-:

• Area of square is greater then Area of Rectangle

Explanation-:

Given ,

• A rectangle 13 m in length and 9 m in breadth.
• A square with 12 m side .

To Find,

• Which shape has bigger area ?

Solution-:

• Area of Rectangle-: length × breadth

Here ,

• Length of Rectangle = 13 m
• Breadth of Rectangle = 9 m

☆ Figure of Rectangle-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 13 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 9 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Now ,

• Area of Rectangle: 13 × 9
• Area of Rectangle = 117 m²

Therefore,

• Area of Rectangle = 117 m²

Now ,

• Area of Square = side × side .

Here ,

• Length of Side = 12 m

☆ Figure of Square-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large x\ cm}\put(4.4,2){\bf\large 12\ m}\end{picture}$

Now ,

• Area of square = 12 × 12
• Area of Square = 144 m²

Therefore,

• Area of Square = 144 m²

Now ,

• Area of Square > Area of Rectangle or 144 m² > 117 m²

Hence ,

• Area of square is greater then Area of Rectangle

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