Question

Which is containing more number of atoms 10gm of C or 10gm of O ????​

Answer 1

Answer:

Answer - carbon

Explanation:

Molecular weight of CaCO3 =100gm

Amount of carbon in 10gm of CaCO3 = 12/100 ×10=1.2gm=12

1.2 =0.1g atom of carbon

Amount of oxygen in 10gm of CaCO3 = 10/48 =4.8gm= 16/4.8 =0.3g atom of oxygen

Amount of calcium in 10gm of CaCO3 = 10/40 =4gm.

∴ The correct answer is

0.3gmatom of oxygen is present in 10gm of CaCO3

.

Answer 2

Answer:

We know ,

n (no. of moles) = given mass (W) / Molar mass (M)

So ,

n ( of Carbon )= 10g /44g

n(of oxygen)= 10g /32g. ( M=32 bcz Oxygen always exists as an O2 molecule)

no. of atoms of carbon =

$(10 \div 44 )\times 6.022 \times {10}^{23}$

$= 5.01 \times {10}^{23}$

no. of oxygen atoms =

$(10 \div 32) \times 6.022 \times {10}^{23}$

$= 3.012 \times {10}^{23}$

So according to the values we get ,

no . of atoms in 10g of C > no. of atoms in 10g of O2

hope it's gonna help....