Question

Which is equivalent to 243 Superscript two-fifths?

3
6
9
12

Answer 1

$Given \: number \: (243)^{\frac{2}{5}}$

/* Resolve 243 into product of prime factors */

3 | 243

_______

3 | 81

_______

3 | 27

_______

3 | 9

_______

*** 3

$243 = 3 \times 3 \times 3 \times 3 \times 3 \\= 3^{5}$

$\red { (243)^{\frac{2}{5}}} \\= \big( 3^{5}\big)^{\frac{2}{5}} \\= 3^{ 5 \times \frac{2}{5} }$

$\boxed { \pink { (a^{m})^{n} = a^{m\times n } }}$

$= 3^{2} \\= 9$

Therefore.,

$\red { (243)^{\frac{2}{5} }} \green {= 9}$

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Answer 2

Answer:

jyt\

Step-by-step explanation:

b