Which is equivalent to (3a + 2b – 2c) + (2a – 4b – c) + (a – 4b + 3c)?
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(3a+2b−2c)+(2a−4b−c)+(a−4b+3c)
=3a+2b−2c+2a−4b−c+a−4b+3c
=3a+2a+a+2b−4b−4b−2c−c+3c
=6a+2b−8b−3c+3c
=6a−6b
=6(a−b)
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