Question

Which is greater 3/8 or 3/5
How??​

Answer 1

Answer:

3/5 is the greater because in order to compare the two numbers, you must convert them to a common factor.

Step-by-step explanation:

• Multiply both upper and lower number with 5
• we get , 3/8=15/40 and 3/5=24/40
• thus 3/5 is greater than 3/8

Answer 2

Answer:

$\frac{3}{5}$ is greater and difference between $\frac{3}{8}$ and $\frac{3}{5}$ is $\frac{9}{40}$

Step-by-step explanation:

Here given two fractions are $\frac{3}{8} \: and \: \frac{3}{5}$

We know,

$8 > 5 \\ \frac{1}{8} < \frac{1}{5} \\ \frac{3}{8} < \frac{3}{5}$

So,

$\frac{3}{5}$ is greater.

Their difference

$= \frac{3}{5} - \frac{3}{8} \\ = 3 \times ( \frac{1}{5} - \frac{1}{8} ) \\ = 3 \times ( \frac{8 - 5}{40} ) \\ = 3 \times \frac{3}{40} \\ = \frac{9}{40}$

This is a problem of number system of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Mathematics problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ2