Which is greater√7-√3 or√5-1
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x = √7 - √3 y = √5 - 1
Reciprocate them and then rationalize the denominators
1/x = [√7 + √3 ] /(7-3) 1/y = [√5 + 1 ] / (5 -1)
clearly, 1/x > 1/y
So x < y
So √7 - √3 < √5 - 1
Reciprocate them and then rationalize the denominators
1/x = [√7 + √3 ] /(7-3) 1/y = [√5 + 1 ] / (5 -1)
clearly, 1/x > 1/y
So x < y
So √7 - √3 < √5 - 1
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