which is greater ? 9xC-11) (08) 6x (16 9
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If (X+9), X-6 and 4 are in GP, then
(X+9)/(X-6) =(X-6)/4
or, 4(X+9) = (X-6)(X-6)
or, X^2 -12X +36 -4X - 36 = 0
or, X(X-16) = 0
X = 0 or 16
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