Question

which is greater in integers (6-8) ×10 or 6-(8×10)​

Answer 1

Answer:

1st one is the greatest negative integer

Answer 2

Given:

• First integer: (6-8)×10
• Second integer: 6-(8×10)

To find:

• Greater integer

Solution:

• First, we solve the 1st given integer=(6-8)×10

$\implies \sf{(6 - 8) \times 10}$

$\implies \sf\blue{60 - 80}$

$\: \: \: \: \: \: \: \: \: \: \: \: \boxed { - 20} \red \bigstar$

• Now, we solve 2nd integer= 6-(8×10)

$\implies \sf {6 - (8 \times 10)}$

$\implies \sf \blue{6 - (80)}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ - 74} \green\bigstar$

So,

$\fbox \orange{Hence, the greater integer is \: ( - 20)}$

Thank you!

@itzshivani