Math, asked by mamtapaliwal131, 9 months ago

which is greater
 \sqrt{5} and \sqrt[14]{7}

Answers

Answered by Anonymous
1

 \sqrt{5}  >  \sqrt[14]{7}  \\  \\  \\

#lovelove!

Answered by amitkumar44481
1

\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Answer:-}}}}}\mid}}}}

 \sqrt{5}  \:  \: and \:  \:   \sqrt[14]{7}  \\  \\  \rightarrow \:  \sqrt{5} \:  \: and \:  \:  \sqrt{ \cancel7}  \frac{1}{ \cancel1 \cancel4}  \\  \\ so \:  \:  \sqrt{5}  >  \sqrt[14]{7} .

<marquee>Follow me

<marquee>Mark as Brainliest

Attachments:
Similar questions