Question

which is having more resistance . 100W bulb or a 60W bulb, operated at 220 V. ​

Answer 1

Answer: 60 W bulb operated at 220 V.

Given:

$\sf Power\:of\:first\:bulb(P_1)=100\:W$

$\sf Power\:of\:second\:bulb(P_2)=60\:W$

$\sf Voltage(V)=200\:V$

To find:

$\sf Which\:bulb\:is\:having\:more\:resistance(R).$

Formula used:

$\boxed{\sf P=\dfrac{V^2}{R}}$

Explanation:

$\sf R=\dfrac{V^2}{P}$

$\sf\underline{ Case\:1:}$

$\sf R_1=\dfrac{220^2}{100}=484\Omega$

$\sf\underline{ Case\:2:}$

$\sf R_2=\dfrac{220^2}{60}=807\Omega$

Hence, the second case, i.e. the 60 W bulb operated at 220 V is having more resistance than case 1.