Which is more stable configuration in d^(5) , d^(10) , d^(3) , d^(2)
PS : (I want the whole process and for clarity, the answer is d^(10) I want process.. )
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Answer:
d^(10)
Explanation:
because in d¹⁰ there are 10 electrons filled with opposite spin and have no vacancy in its orbital.
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