Question

Which is not a root polynomial (9x^3+ax^2+b) a and b are integers?

Answer 1

Complex root in a polynomial always occur in pairs it means that if one complex no is a root of the polynomial given then its conjugate must also be the root of that particular polynomial. Thus if 3 +sqrt7 is one of its root then 3 - sqrt7 must be the another root.

Answer 2

Answer:

-9

Step-by-step explanation:

answer is -9 .

If -9 is a root, then 9*(-9)^3 +a*9^2 +b =0

then , -1/81 +81a +b = 0

81a+ b= 1/81, which is not possible, since a and b are integers.

So -9 is not a root.

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