Which is real roots a) x2+2x+1=0 b) x2-x-2=0 c) x2-2x+1=0 d) x2+x+2=0
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option a has real roots because it is (X+1)2.
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x²-2x+1=0
=>x²-1x-1x+1=0
=>x(x-1)-1(x-1)=0
=>(x-1)(x-1)=0
Therefore, x²-2x+1=0
has the real roots
=>x²-1x-1x+1=0
=>x(x-1)-1(x-1)=0
=>(x-1)(x-1)=0
Therefore, x²-2x+1=0
has the real roots
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