Question

Which is the 51th term in the
given series:
3,7,11,15,....
a)201.
b)205.
c)203.
d)207.

Answer 1

a = 3

d = 4

therefore the 51st term is  = a + 50 d

this is a formula where  u add the first term and one d multiplied by one number less than wanted number

so

3+ 50 * 4 = 3 + 200 = 203

therefore

option c) 203 is correct

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Answer 2

51term= 3+(51-1)4. [d=4 , n=51, a=3]
51 term = 3+50*4
51 term= 3+200
51term = 203
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