Which is the correct answer
Attachments:
Answers
Answered by
0
Answer:
Option (A) is correct.
Explanation:
Let 11^x = 3^y = 99^z = k
i) 11^x = k => 11 = k^1/x
ii) 3^y = k => 3 = k^1/y
iii) 99^z = k => 99 = k^1/z
Now ,
11×3×3 = 99
=> k^1/x *k^1/y*k^1/y = k^1/z
=> k^(1/x+1/y+1/y)=k^1/z
=> 1/x+2/y = 1/z
=> 1/x+1/y = 1/z-1/y
=> 1/x+1/y+1/z = 1/z-1/y+1/z
=> 1/x+1/y+1/z = 2/z-1/y
Therefore,.
Option (A) is correct.
••••
Similar questions