Math, asked by dipal99, 11 months ago

Which is the correct answer​

Attachments:

Answers

Answered by mysticd
0

Answer:

Option (A) is correct.

Explanation:

Let 11^x = 3^y = 99^z = k

i) 11^x = k => 11 = k^1/x

ii) 3^y = k => 3 = k^1/y

iii) 99^z = k => 99 = k^1/z

Now ,

11×3×3 = 99

=> k^1/x *k^1/y*k^1/y = k^1/z

=> k^(1/x+1/y+1/y)=k^1/z

=> 1/x+2/y = 1/z

=> 1/x+1/y = 1/z-1/y

=> 1/x+1/y+1/z = 1/z-1/y+1/z

=> 1/x+1/y+1/z = 2/z-1/y

Therefore,.

Option (A) is correct.

••••

Similar questions