which is the correct option...? and also explain it.....
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This is a clear explanation
,For your question in the comment Here Tan (A + B )is a formula ,we can use it to see that solving it further will give the equation we are requesting
Please Comment If you have A doubt
if This helped please like it and mark Brainliest
,For your question in the comment Here Tan (A + B )is a formula ,we can use it to see that solving it further will give the equation we are requesting
Please Comment If you have A doubt
if This helped please like it and mark Brainliest
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Avijith:
i have given it in the answer now
it is crrt u Can go with it
hmm
yes
b is correct
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HEY Buddy....!! here is ur answer
Given that... A+B = π/4
On taking 'tan' both the sides....
tan(A+B) = tan π/4 [ tan π/4 = 1 ]
(tanA+tanB)/(1–tanAtanB) = 1
{ As we know that, tan(A+B)=(tanA+tanB)/(1-tanAtanB) }
=> tanA+tanB = 1-tanAtanB
On adding 1 both the side....
=> 1+tanA+tanB = 1+1-tanAtanB
=> 1+tanA+tanB+tanAtanB = 2
=> (1+tanA)+tanB(1+tanA) = 2
=> (1+tanA)(1+tanB) = 2 <<< Ans.
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Given that... A+B = π/4
On taking 'tan' both the sides....
tan(A+B) = tan π/4 [ tan π/4 = 1 ]
(tanA+tanB)/(1–tanAtanB) = 1
{ As we know that, tan(A+B)=(tanA+tanB)/(1-tanAtanB) }
=> tanA+tanB = 1-tanAtanB
On adding 1 both the side....
=> 1+tanA+tanB = 1+1-tanAtanB
=> 1+tanA+tanB+tanAtanB = 2
=> (1+tanA)+tanB(1+tanA) = 2
=> (1+tanA)(1+tanB) = 2 <<< Ans.
I hope it will be helpful for you....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
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